Integrand size = 22, antiderivative size = 270 \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \arctan \left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {1+2 x}}{\sqrt {10 \left (-2+\sqrt {35}\right )}}\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \arctan \left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}+10 \sqrt {1+2 x}}{\sqrt {10 \left (-2+\sqrt {35}\right )}}\right )-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right ) \]
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Time = 0.26 (sec) , antiderivative size = 270, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {752, 840, 1183, 648, 632, 210, 642} \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \arctan \left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \arctan \left (\frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )-\frac {\sqrt {2 x+1} (5-4 x)}{31 \left (5 x^2+3 x+2\right )}-\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right ) \]
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Rule 210
Rule 632
Rule 642
Rule 648
Rule 752
Rule 840
Rule 1183
Rubi steps \begin{align*} \text {integral}& = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {1}{31} \int \frac {9+4 x}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )} \, dx \\ & = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {2}{31} \text {Subst}\left (\int \frac {14+4 x^2}{7-4 x^2+5 x^4} \, dx,x,\sqrt {1+2 x}\right ) \\ & = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {\text {Subst}\left (\int \frac {14 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-\left (14-4 \sqrt {\frac {7}{5}}\right ) x}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )}{31 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {\text {Subst}\left (\int \frac {14 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+\left (14-4 \sqrt {\frac {7}{5}}\right ) x}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )}{31 \sqrt {14 \left (2+\sqrt {35}\right )}} \\ & = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {1}{155} \left (2+\sqrt {35}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )+\frac {1}{155} \left (2+\sqrt {35}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \text {Subst}\left (\int \frac {-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 x}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \text {Subst}\left (\int \frac {\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 x}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right ) \\ & = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )-\frac {1}{155} \left (2 \left (2+\sqrt {35}\right )\right ) \text {Subst}\left (\int \frac {1}{\frac {2}{5} \left (2-\sqrt {35}\right )-x^2} \, dx,x,-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right )-\frac {1}{155} \left (2 \left (2+\sqrt {35}\right )\right ) \text {Subst}\left (\int \frac {1}{\frac {2}{5} \left (2-\sqrt {35}\right )-x^2} \, dx,x,\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right ) \\ & = -\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\sqrt {\frac {5}{2 \left (-2+\sqrt {35}\right )}} \left (\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-2 \sqrt {1+2 x}\right )\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\sqrt {\frac {5}{2 \left (-2+\sqrt {35}\right )}} \left (\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right )\right )-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right ) \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.84 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.48 \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=\frac {2 \left (\frac {155 \sqrt {1+2 x} (-5+4 x)}{4+6 x+10 x^2}+\sqrt {155 \left (218+31 i \sqrt {31}\right )} \arctan \left (\sqrt {\frac {1}{7} \left (-2-i \sqrt {31}\right )} \sqrt {1+2 x}\right )+\sqrt {155 \left (218-31 i \sqrt {31}\right )} \arctan \left (\sqrt {\frac {1}{7} i \left (2 i+\sqrt {31}\right )} \sqrt {1+2 x}\right )\right )}{4805} \]
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Time = 0.56 (sec) , antiderivative size = 312, normalized size of antiderivative = 1.16
method | result | size |
pseudoelliptic | \(-\frac {3100 \left (\frac {39 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (x^{2}+\frac {3}{5} x +\frac {2}{5}\right ) \left (\sqrt {5}-\frac {20 \sqrt {7}}{39}\right ) \ln \left (\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{620}-\frac {39 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (x^{2}+\frac {3}{5} x +\frac {2}{5}\right ) \left (\sqrt {5}-\frac {20 \sqrt {7}}{39}\right ) \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{620}-\frac {2 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \left (-\frac {5}{4}+x \right ) \sqrt {1+2 x}}{5}+\left (\arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )-\arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )\right ) \left (x^{2}+\frac {3}{5} x +\frac {2}{5}\right ) \left (\sqrt {5}\, \sqrt {7}+2\right )\right )}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \left (48050 x^{2}+28830 x +19220\right )}\) | \(312\) |
derivativedivides | \(\frac {\frac {8 \left (1+2 x \right )^{\frac {3}{2}}}{155}-\frac {28 \sqrt {1+2 x}}{155}}{\left (1+2 x \right )^{2}+\frac {3}{5}-\frac {8 x}{5}}+\frac {\left (-39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \ln \left (\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{9610}+\frac {2 \left (62 \sqrt {5}\, \sqrt {7}+\frac {\left (-39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{10}\right ) \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {\left (39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{9610}+\frac {2 \left (62 \sqrt {5}\, \sqrt {7}-\frac {\left (39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{10}\right ) \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\) | \(415\) |
default | \(\frac {\frac {8 \left (1+2 x \right )^{\frac {3}{2}}}{155}-\frac {28 \sqrt {1+2 x}}{155}}{\left (1+2 x \right )^{2}+\frac {3}{5}-\frac {8 x}{5}}+\frac {\left (-39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \ln \left (\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{9610}+\frac {2 \left (62 \sqrt {5}\, \sqrt {7}+\frac {\left (-39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{10}\right ) \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {\left (39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right )}{9610}+\frac {2 \left (62 \sqrt {5}\, \sqrt {7}-\frac {\left (39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-20 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{10}\right ) \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\) | \(415\) |
trager | \(\frac {\left (-5+4 x \right ) \sqrt {1+2 x}}{155 x^{2}+93 x +62}+\frac {2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right ) \ln \left (\frac {12147040 \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right ) \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{4} x +14700200 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right ) x +4858816 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right )-84010620 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} \sqrt {1+2 x}+4334340 \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right ) x +2471072 \operatorname {RootOf}\left (\textit {\_Z}^{2}+24025 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2}+16895\right )+165085385 \sqrt {1+2 x}}{620 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} x +125 x -124}\right )}{4805}+\frac {2 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right ) \ln \left (\frac {60735200 x \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{5}+11920120 x \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{3}-24294080 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{3}+2710020 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} \sqrt {1+2 x}+19068 x \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )-4728864 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )+7231091 \sqrt {1+2 x}}{620 \operatorname {RootOf}\left (76880 \textit {\_Z}^{4}+54064 \textit {\_Z}^{2}+15463\right )^{2} x +311 x +124}\right )}{31}\) | \(447\) |
risch | \(\frac {\left (-5+4 x \right ) \sqrt {1+2 x}}{155 x^{2}+93 x +62}-\frac {39 \ln \left (\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{9610}+\frac {2 \ln \left (\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{961}-\frac {39 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \left (2 \sqrt {5}\, \sqrt {7}+4\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \sqrt {7}}{31 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {39 \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{9610}-\frac {2 \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{961}-\frac {39 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \left (2 \sqrt {5}\, \sqrt {7}+4\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \sqrt {7}}{31 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\) | \(633\) |
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Result contains complex when optimal does not.
Time = 0.38 (sec) , antiderivative size = 247, normalized size of antiderivative = 0.91 \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=-\frac {\sqrt {155} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {124 i \, \sqrt {31} - 872} \log \left (\sqrt {155} \sqrt {124 i \, \sqrt {31} - 872} {\left (4 i \, \sqrt {31} - 31\right )} + 14570 \, \sqrt {2 \, x + 1}\right ) - \sqrt {155} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {124 i \, \sqrt {31} - 872} \log \left (\sqrt {155} \sqrt {124 i \, \sqrt {31} - 872} {\left (-4 i \, \sqrt {31} + 31\right )} + 14570 \, \sqrt {2 \, x + 1}\right ) - \sqrt {155} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {-124 i \, \sqrt {31} - 872} \log \left (\sqrt {155} {\left (4 i \, \sqrt {31} + 31\right )} \sqrt {-124 i \, \sqrt {31} - 872} + 14570 \, \sqrt {2 \, x + 1}\right ) + \sqrt {155} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {-124 i \, \sqrt {31} - 872} \log \left (\sqrt {155} {\left (-4 i \, \sqrt {31} - 31\right )} \sqrt {-124 i \, \sqrt {31} - 872} + 14570 \, \sqrt {2 \, x + 1}\right ) - 310 \, {\left (4 \, x - 5\right )} \sqrt {2 \, x + 1}}{9610 \, {\left (5 \, x^{2} + 3 \, x + 2\right )}} \]
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\[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=\int \frac {\left (2 x + 1\right )^{\frac {3}{2}}}{\left (5 x^{2} + 3 x + 2\right )^{2}}\, dx \]
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\[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=\int { \frac {{\left (2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 622 vs. \(2 (187) = 374\).
Time = 0.67 (sec) , antiderivative size = 622, normalized size of antiderivative = 2.30 \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=\text {Too large to display} \]
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Time = 9.86 (sec) , antiderivative size = 208, normalized size of antiderivative = 0.77 \[ \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx=-\frac {\frac {28\,\sqrt {2\,x+1}}{155}-\frac {8\,{\left (2\,x+1\right )}^{3/2}}{155}}{{\left (2\,x+1\right )}^2-\frac {8\,x}{5}+\frac {3}{5}}+\frac {\sqrt {155}\,\mathrm {atan}\left (\frac {\sqrt {155}\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}\,128{}\mathrm {i}}{3003125\,\left (\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}+\frac {256\,\sqrt {31}\,\sqrt {155}\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}}{93096875\,\left (\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}\right )\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,2{}\mathrm {i}}{4805}-\frac {\sqrt {155}\,\mathrm {atan}\left (\frac {\sqrt {155}\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}\,128{}\mathrm {i}}{3003125\,\left (-\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}-\frac {256\,\sqrt {31}\,\sqrt {155}\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}}{93096875\,\left (-\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}\right )\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,2{}\mathrm {i}}{4805} \]
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